In this video I will, in case #4, I will solve the differential equation for the theta function (zenith direction, y-z plane) when n=1,l=2, and m(l)=0. From previous video we found f(x)=(1/2((3x^2)-1) for l=2 and m(l)=0 thus ThetaFunction(theta)=(1/2((3(cos(theta))x^2)-1). Then we will into the differential equation to see if the left-side will equal the right-side, or 0=0?