In this video I will find the constant A. We have shown (as seen in the previous video) that the solution to the differential equation for n=1,l=2, and m(l)=0 for the ThetaFunction=(1/2((3(cos(theta))x^2)-1), or the zenith direction, y-z plane. So to find A=? we need to normalize the function: 1=2integral(ThetaFunction)^2.